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Popular >

center x^2+y^2=8

Solution

center

x^{2} + y^{2} = 8

Solution

(0, 0)

Solution steps

x^{2} + y^{2} = 8

Rewrite

x^{2} + y^{2} = 8

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = (8)^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 8

And the center is:

(0, 0)

Popular Examples

center (x-1)^2+(y+3)^2=4 center

(x - 1)^{2} + (y + 3)^{2} = 4

center x^2+(y-1)^2=25 center

x^{2} + (y - 1)^{2} = 25

center x^2-4x+y^2-4y-8=0 center

x^{2} - 4 x + y^{2} - 4 y - 8 = 0

center x^2+y^2-6x+4y+4=0 center

x^{2} + y^{2} - 6 x + 4 y + 4 = 0

center x^2+y^2+2x-6y=0 center

x^{2} + y^{2} + 2 x - 6 y = 0

Frequently Asked Questions (FAQ)

What is the center x^2+y^2=8 ?
The center x^2+y^2=8 is (0,0)