What is the center x^2+y^2-25=0 ?

The center x^2+y^2-25=0 is (0,0)

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center x^2+y^2-25=0

center

x^{2} + y^{2} - 25 = 0

(0, 0)

Solution steps

x^{2} + y^{2} - 25 = 0

Rewrite

x^{2} + y^{2} - 25 = 0

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 5

And the center is:

(0, 0)

(x + 2)^{2} + y^{2} = 25

144 x^{2} + 144 y^{2} + 72 x + 192 y + 37 = 0

4 x^{2} + 4 y^{2} + 40 x - 32 y = 5

4 x^{2} + 4 y^{2} + 8 x - y = 0

(x + 2)^{2} + (y + 5)^{2} = 16