What is the center (x+12)^2+(y-9)^2=35 ?

The center (x+12)^2+(y-9)^2=35 is (-12,9)

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center (x+12)^2+(y-9)^2=35

center

(x + 12)^{2} + (y - 9)^{2} = 35

(- 12, 9)

Solution steps

(x + 12)^{2} + (y - 9)^{2} = 35

Rewrite

(x + 12)^{2} + (y - 9)^{2} = 35

in the form of the standard circle equation

(x - (- 12))^{2} + (y - 9)^{2} = (35)^{2}

Therefore the circle properties are:

(a, b) = (- 12, 9), r = 35

And the center is:

(- 12, 9)

x^{2} + y^{2} = 10

(x + 1)^{2} + (y + 3)^{2} = 5

(x + 1)^{2} + y^{2} = 4

(x + 3)^{2} + (y - 1)^{2} = 9

2 x^{2} + 2 y^{2} - 17 x = 0

What is the center (x+12)^2+(y-9)^2=35 ?
The center (x+12)^2+(y-9)^2=35 is (-12,9)