What is the center (x+2)^2+(y-3)^2=25 ?

The center (x+2)^2+(y-3)^2=25 is (-2,3)

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center (x+2)^2+(y-3)^2=25

center

(x + 2)^{2} + (y - 3)^{2} = 25

(- 2, 3)

Solution steps

(x + 2)^{2} + (y - 3)^{2} = 25

Rewrite

(x + 2)^{2} + (y - 3)^{2} = 25

in the form of the standard circle equation

(x - (- 2))^{2} + (y - 3)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (- 2, 3), r = 5

And the center is:

(- 2, 3)

x^{2} + y^{2} + 2 x = 3 y

x^{2} + 8 x + y^{2} + 2 y + 8 = 0

x^{2} + 6 x + y^{2} - 3 y = - \frac{1}{4}

x^{2} + y^{2} - 3 x + 4 y = 0

x^{2} + 4 x + 10 y + y^{2} + 3 = 0