What is the center x^2+y^2-6x+5=0 ?

The center x^2+y^2-6x+5=0 is (3,0)

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center x^2+y^2-6x+5=0

center

x^{2} + y^{2} - 6 x + 5 = 0

(3, 0)

Solution steps

x^{2} + y^{2} - 6 x + 5 = 0

Rewrite

x^{2} + y^{2} - 6 x + 5 = 0

in the form of the standard circle equation

(x - 3)^{2} + (y - 0)^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (3, 0), r = 2

And the center is:

(3, 0)

(x - 1)^{2} + (y + 4)^{2} = 36

x^{2} + y^{2} + 14 x - 12 y + 4 = 0

(x + 2)^{2} + (y - 4)^{2} = 25

x^{2} + y^{2} + 2 x - 4 y = 76

(x - 3)^{2} + (y - 4)^{2} = 4