What is the center x^2+(y-5)^2=36 ?

The center x^2+(y-5)^2=36 is (0,5)

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center x^2+(y-5)^2=36

center

x^{2} + (y - 5)^{2} = 36

(0, 5)

Solution steps

x^{2} + (y - 5)^{2} = 36

Rewrite

x^{2} + (y - 5)^{2} = 36

in the form of the standard circle equation

(x - 0)^{2} + (y - 5)^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (0, 5), r = 6

And the center is:

(0, 5)

x^{2} + y^{2} + 12 x - 12 y + 36 = 0

x^{2} + (y - 5)^{2} = 16

(x + 1)^{2} + y^{2} = 25

4 x^{2} + 4 y^{2} - 8 x - 4 y = 11

(x + 5)^{2} + (y + 4)^{2} = 9