What is the center x^2+y^2-18x-6y-13=8 ?

The center x^2+y^2-18x-6y-13=8 is (9,3)

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center x^2+y^2-18x-6y-13=8

center

x^{2} + y^{2} - 18 x - 6 y - 13 = 8

(9, 3)

Solution steps

x^{2} + y^{2} - 18 x - 6 y - 13 = 8

Rewrite

x^{2} + y^{2} - 18 x - 6 y - 13 = 8

in the form of the standard circle equation

(x - 9)^{2} + (y - 3)^{2} = (111)^{2}

Therefore the circle properties are:

(a, b) = (9, 3), r = 111

And the center is:

(9, 3)

(x + 1)^{2} + (y - 2)^{2} = 25

4 (x - 3)^{2} + 4 y^{2} = 4

x^{2} + (y - 1)^{2} = 16

x^{2} + y^{2} + 2 x - 8 y - 19 = 0

2 x^{2} + 2 y^{2} + 28 x - 8 y + 4 = 0

What is the center x^2+y^2-18x-6y-13=8 ?
The center x^2+y^2-18x-6y-13=8 is (9,3)