What is the center x^2+y^2-20x-20y+100=0 ?

The center x^2+y^2-20x-20y+100=0 is (10,10)

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center x^2+y^2-20x-20y+100=0

center

x^{2} + y^{2} - 20 x - 20 y + 100 = 0

(10, 10)

Solution steps

x^{2} + y^{2} - 20 x - 20 y + 100 = 0

Rewrite

x^{2} + y^{2} - 20 x - 20 y + 100 = 0

in the form of the standard circle equation

(x - 10)^{2} + (y - 10)^{2} = 1 0^{2}

Therefore the circle properties are:

(a, b) = (10, 10), r = 10

And the center is:

(10, 10)

X^{2} + Y^{2} + 2 X - 6 Y = 0

4 x^{2} + 4 y^{2} = 64

(x - 2)^{2} + (y + 5)^{2} = 9

36 x^{2} - 36 x + 36 y^{2} + 72 y = 279

x^{2} + y^{2} + 6 y + 2 = 0

What is the center x^2+y^2-20x-20y+100=0 ?
The center x^2+y^2-20x-20y+100=0 is (10,10)