What is the center x^2+y^2+20x-18y+145=0 ?

The center x^2+y^2+20x-18y+145=0 is (-10,9)

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center x^2+y^2+20x-18y+145=0

center

x^{2} + y^{2} + 20 x - 18 y + 145 = 0

(- 10, 9)

Solution steps

x^{2} + y^{2} + 20 x - 18 y + 145 = 0

Rewrite

x^{2} + y^{2} + 20 x - 18 y + 145 = 0

in the form of the standard circle equation

(x - (- 10))^{2} + (y - 9)^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (- 10, 9), r = 6

And the center is:

(- 10, 9)

(x + 4)^{2} + y^{2} = 4

x^{2} + y^{2} - 3 x - 4 y + 4 = 0

2 x^{2} + 2 y^{2} + 4 x - 8 y - 22 = 0

x^{2} + y^{2} - 4 x + 2 y - 15 = 0

(x - 1)^{2} + (y + 4)^{2} = 9

What is the center x^2+y^2+20x-18y+145=0 ?
The center x^2+y^2+20x-18y+145=0 is (-10,9)