What is the center (x-5)^2+(y-6)^2=36 ?

The center (x-5)^2+(y-6)^2=36 is (5,6)

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center (x-5)^2+(y-6)^2=36

center

(x - 5)^{2} + (y - 6)^{2} = 36

(5, 6)

Solution steps

(x - 5)^{2} + (y - 6)^{2} = 36

Rewrite

(x - 5)^{2} + (y - 6)^{2} = 36

in the form of the standard circle equation

(x - 5)^{2} + (y - 6)^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (5, 6), r = 6

And the center is:

(5, 6)

(x - 5)^{2} + (y + 7)^{2} = 9

x^{2} + y^{2} - 4 x - 6 y - 23 = 0

x^{2} + y^{2} - x + 2 y + 1 = 0

(x - 2)^{2} + (y - 3)^{2} = 49

(x - 5)^{2} + (y + 7)^{2} = 4