What is the center-20-x^2=-16x-20y+y^2 ?

The center-20-x^2=-16x-20y+y^2 is (8,10)

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center-20-x^2=-16x-20y+y^2

center

- 20 - x^{2} = - 16 x - 20 y + y^{2}

(8, 10)

Solution steps

- 20 - x^{2} = - 16 x - 20 y + y^{2}

Rewrite

- 20 - x^{2} = - 16 x - 20 y + y^{2}

in the form of the standard circle equation

(x - 8)^{2} + (y - 10)^{2} = 1 2^{2}

Therefore the circle properties are:

(a, b) = (8, 10), r = 12

And the center is:

(8, 10)

x^{2} + y^{2} = 4 x

x^{2} + y^{2} - 8 x - 4 y - 16 = 0

x^{2} + y^{2} = 72

(x - 3)^{2} + (y - 2)^{2} = 49

(x - 1)^{2} + (y + 5)^{2} = 16

What is the center-20-x^2=-16x-20y+y^2 ?
The center-20-x^2=-16x-20y+y^2 is (8,10)