What is the center (x+5)^2+(y-2)^2=25 ?

The center (x+5)^2+(y-2)^2=25 is (-5,2)

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center (x+5)^2+(y-2)^2=25

center

(x + 5)^{2} + (y - 2)^{2} = 25

(- 5, 2)

Solution steps

(x + 5)^{2} + (y - 2)^{2} = 25

Rewrite

(x + 5)^{2} + (y - 2)^{2} = 25

in the form of the standard circle equation

(x - (- 5))^{2} + (y - 2)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (- 5, 2), r = 5

And the center is:

(- 5, 2)

x^{2} + y^{2} + 4 x + 6 y = 23

(x - 5)^{2} + (y + 2)^{2} = 15

x^{2} + (y + 5)^{2} = 100

(x + 5)^{2} + y^{2} = 64

\frac{x ^{2}}{49} + \frac{y ^{2}}{49} = 1