What is the center x^2+y^2+2x-27/2 y+20=0 ?

The center x^2+y^2+2x-27/2 y+20=0 is (-1, 27/4)

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center x^2+y^2+2x-27/2 y+20=0

center

x^{2} + y^{2} + 2 x - \frac{27}{2} y + 20 = 0

(- 1, \frac{27}{4})

Solution steps

x^{2} + y^{2} + 2 x - \frac{27}{2} y + 20 = 0

Rewrite

x^{2} + y^{2} + 2 x - \frac{27}{2} y + 20 = 0

in the form of the standard circle equation

(x - (- 1))^{2} + (y - \frac{27}{4})^{2} = (\frac{5 17}{4})^{2}

Therefore the circle properties are:

(a, b) = (- 1, \frac{27}{4}), r = \frac{5 17}{4}

And the center is:

(- 1, \frac{27}{4})

x^{2} + (y - 2)^{2} = 1

x^{2} + y^{2} - 12 x - 12 y + 36 = 0

(x - 3)^{2} + (y + 9)^{2} = 9^{2}

x^{2} + y^{2} = 289

(x + 1)^{2} + (y + 2)^{2} = 25

What is the center x^2+y^2+2x-27/2 y+20=0 ?
The center x^2+y^2+2x-27/2 y+20=0 is (-1, 27/4)