What is the center x^2+y^2-7x=15-2y ?

The center x^2+y^2-7x=15-2y is (7/2 ,-1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

center x^2+y^2-7x=15-2y

center

x^{2} + y^{2} - 7 x = 15 - 2 y

(\frac{7}{2}, - 1)

Solution steps

x^{2} + y^{2} - 7 x = 15 - 2 y

Rewrite

x^{2} + y^{2} - 7 x = 15 - 2 y

in the form of the standard circle equation

(x - \frac{7}{2})^{2} + (y - (- 1))^{2} = (\frac{113}{2})^{2}

Therefore the circle properties are:

(a, b) = (\frac{7}{2}, - 1), r = \frac{113}{2}

And the center is:

(\frac{7}{2}, - 1)

x^{2} + y^{2} = 9

x^{2} + y^{2} = 4

x^{2} + y^{2} - 4 x + 10 y + 13 = 0

x^{2} + y^{2} = 81

x^{2} + y^{2} - 6 x - 8 y = 0