What is the radius x^2+y^2-2x+6y-15=0 ?

The radius x^2+y^2-2x+6y-15=0 is r=5

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radius x^2+y^2-2x+6y-15=0

radius

x^{2} + y^{2} - 2 x + 6 y - 15 = 0

r = 5

Solution steps

x^{2} + y^{2} - 2 x + 6 y - 15 = 0

Rewrite

x^{2} + y^{2} - 2 x + 6 y - 15 = 0

in the form of the standard circle equation

(x - 1)^{2} + (y - (- 3))^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (1, - 3), r = 5

And the radius is:

r = 5

2 x^{2} + 2 y^{2} - 14 x + 18 y = 7

x^{2} = 16 - y^{2}

x^{2} + y^{2} = 100

2 x^{2} - 6 x + 2 y^{2} + 2 y = 45

x^{2} + y^{2} - 4 x - 6 y - 12 = 0