What is the radius (x+5)^2+(y+4)^2=9 ?

The radius (x+5)^2+(y+4)^2=9 is r=3

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radius (x+5)^2+(y+4)^2=9

radius

(x + 5)^{2} + (y + 4)^{2} = 9

r = 3

Solution steps

(x + 5)^{2} + (y + 4)^{2} = 9

Rewrite

(x + 5)^{2} + (y + 4)^{2} = 9

in the form of the standard circle equation

(x - (- 5))^{2} + (y - (- 4))^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (- 5, - 4), r = 3

And the radius is:

r = 3

(x - 3)^{2} + (y + 1)^{2} = 16

16 x^{2} + 16 y^{2} - 16 x + 24 y - 3 = 0

4 x^{2} + 4 y^{2} - 8 y - 5 = 0

x^{2} + y^{2} - 7 x = 36 - 4 y

(x - 5)^{2} + (y + 1)^{2} = 16