What is the radius (x+6)^2+(y+5)^2=8 ?

The radius (x+6)^2+(y+5)^2=8 is r=sqrt(8)

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radius (x+6)^2+(y+5)^2=8

radius

(x + 6)^{2} + (y + 5)^{2} = 8

r = 8

Solution steps

(x + 6)^{2} + (y + 5)^{2} = 8

Rewrite

(x + 6)^{2} + (y + 5)^{2} = 8

in the form of the standard circle equation

(x - (- 6))^{2} + (y - (- 5))^{2} = (8)^{2}

Therefore the circle properties are:

(a, b) = (- 6, - 5), r = 8

And the radius is:

r = 8

(x - 4)^{2} + (y + 5)^{2} = 49

x^{2} + y^{2} + 6 y + 2 = 0

x^{2} + y^{2} - 4 x - 7 = 0

2 x^{2} + 2 y^{2} - 17 x = 0

x^{2} + y^{2} - 4 x + 10 y + 20 = 0

What is the radius (x+6)^2+(y+5)^2=8 ?
The radius (x+6)^2+(y+5)^2=8 is r=sqrt(8)