What is the radius x^2+y^2-10x+10y+49=0 ?

The radius x^2+y^2-10x+10y+49=0 is r=1

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radius x^2+y^2-10x+10y+49=0

radius

x^{2} + y^{2} - 10 x + 10 y + 49 = 0

r = 1

Solution steps

x^{2} + y^{2} - 10 x + 10 y + 49 = 0

Rewrite

x^{2} + y^{2} - 10 x + 10 y + 49 = 0

in the form of the standard circle equation

(x - 5)^{2} + (y - (- 5))^{2} = 1^{2}

Therefore the circle properties are:

(a, b) = (5, - 5), r = 1

And the radius is:

r = 1

x^{2} + (y - 1)^{2} = 64

x^{2} + (y - 1)^{2} = 16

x^{2} + y^{2} + 10 x - 6 y + 18 = 0

(x + 8)^{2} + (y + 5)^{2} = 3^{2}

(x + 1)^{2} + (y - 2)^{2} = 9

What is the radius x^2+y^2-10x+10y+49=0 ?
The radius x^2+y^2-10x+10y+49=0 is r=1