What is the radius (x-2)^2+(y+4)^2=4 ?

The radius (x-2)^2+(y+4)^2=4 is r=2

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radius (x-2)^2+(y+4)^2=4

radius

(x - 2)^{2} + (y + 4)^{2} = 4

r = 2

Solution steps

(x - 2)^{2} + (y + 4)^{2} = 4

Rewrite

(x - 2)^{2} + (y + 4)^{2} = 4

in the form of the standard circle equation

(x - 2)^{2} + (y - (- 4))^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (2, - 4), r = 2

And the radius is:

r = 2

(x + 1)^{2} + (y - 1)^{2} = 40

x^{2} + y^{2} - 2 x - 8 y - 19 = 0 (1.5)

x^{2} + y^{2} + 10 x + 8 y - 4 = 0

(x - 3)^{2} + (y - 5)^{2} = 24

x^{2} + y^{2} + 4 x - 6 y - 12 = 0