What is the radius 3x^2+3y^2-17x=0 ?

The radius 3x^2+3y^2-17x=0 is r= 17/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

radius 3x^2+3y^2-17x=0

radius

3 x^{2} + 3 y^{2} - 17 x = 0

r = \frac{17}{6}

Solution steps

3 x^{2} + 3 y^{2} - 17 x = 0

Rewrite

3 x^{2} + 3 y^{2} - 17 x = 0

in the form of the standard circle equation

(x - \frac{17}{6})^{2} + (y - 0)^{2} = (\frac{17}{6})^{2}

Therefore the circle properties are:

(a, b) = (\frac{17}{6}, 0), r = \frac{17}{6}

And the radius is:

r = \frac{17}{6}

x^{2} + y^{2} - 6 x + 5 = 0

2 x^{2} + 2 y^{2} - 9 x - 18 y - 80 = 0

5 x^{2} + 5 y^{2} + 10 x + 2 y + 3 = 0

x^{2} + y^{2} = 48

x^{2} + y^{2} - x + 6 y + 9 = 0