What is the radius (x-4)^2+(y+12)^2=17^2 ?

The radius (x-4)^2+(y+12)^2=17^2 is r=17

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radius (x-4)^2+(y+12)^2=17^2

radius

(x - 4)^{2} + (y + 12)^{2} = 1 7^{2}

r = 17

Solution steps

(x - 4)^{2} + (y + 12)^{2} = 1 7^{2}

Rewrite

(x - 4)^{2} + (y + 12)^{2} = 1 7^{2}

in the form of the standard circle equation

(x - 4)^{2} + (y - (- 12))^{2} = 1 7^{2}

Therefore the circle properties are:

(a, b) = (4, - 12), r = 17

And the radius is:

r = 17

x^{2} + y^{2} - 6 x + 2 y = 6

x^{2} + y^{2} - 6 x - 10 y + 9 = 0

x^{2} + y^{2} + 8 x - 14 y + 1 = 0

3 x^{2} + 3 y^{2} - 24 x + 6 y - 24 = 0

x^{2} + y^{2} - 4 x + 12 x = 16

What is the radius (x-4)^2+(y+12)^2=17^2 ?
The radius (x-4)^2+(y+12)^2=17^2 is r=17