What is the radius x^2+8x+y^2+2y+8=0 ?

The radius x^2+8x+y^2+2y+8=0 is r=3

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radius x^2+8x+y^2+2y+8=0

radius

x^{2} + 8 x + y^{2} + 2 y + 8 = 0

r = 3

Solution steps

x^{2} + 8 x + y^{2} + 2 y + 8 = 0

Rewrite

x^{2} + 8 x + y^{2} + 2 y + 8 = 0

in the form of the standard circle equation

(x - (- 4))^{2} + (y - (- 1))^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (- 4, - 1), r = 3

And the radius is:

r = 3

x^{2} + y^{2} = 13

x^{2} + y^{2} = 11

x^{2} + y^{2} = 19

x^{2} + y^{2} + x + y = 0

x^{2} + y^{2} - 6 x - 10 y + 18 = 0