What is the radius x^2+y^2-10x+6y+18=0 ?

The radius x^2+y^2-10x+6y+18=0 is r=4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

radius x^2+y^2-10x+6y+18=0

radius

x^{2} + y^{2} - 10 x + 6 y + 18 = 0

r = 4

Solution steps

x^{2} + y^{2} - 10 x + 6 y + 18 = 0

Rewrite

x^{2} + y^{2} - 10 x + 6 y + 18 = 0

in the form of the standard circle equation

(x - 5)^{2} + (y - (- 3))^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (5, - 3), r = 4

And the radius is:

r = 4

2 x^{2} + 2 y^{2} + 10 x = 2 y + 7

x^{2} + y^{2} - 16 y + 39 = 0

x^{2} + y^{2} - 4 x + 6 y - 12 = 0

x^{2} + y^{2} + 8 y = 2 x + 20

(x - 2)^{2} + (y - 5)^{2} = 49