What is the radius (x^2-2)+(y^2+4)=16 ?

The radius (x^2-2)+(y^2+4)=16 is r=sqrt(14)

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radius (x^2-2)+(y^2+4)=16

radius

(x^{2} - 2) + (y^{2} + 4) = 16

r = 14

Solution steps

x^{2} - 2 + (y^{2} + 4) = 16

Rewrite

x^{2} - 2 + (y^{2} + 4) = 16

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = (14)^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 14

And the radius is:

r = 14

4 x^{2} + 4 x + 4 y^{2} - 16 y - 19 = 0

2 x^{2} + 2 y^{2} + 8 x - 12 y - 26 = 0

x^{2} + y^{2} + 10 x - 8 y + 25 = 0

x^{2} + y^{2} + 3 x - 4 y - 15 = 0

(x + 6)^{2} + y^{2} = 1

What is the radius (x^2-2)+(y^2+4)=16 ?
The radius (x^2-2)+(y^2+4)=16 is r=sqrt(14)