What is the radius x^2+2x+y^2-2y=-1 ?

The radius x^2+2x+y^2-2y=-1 is r=1

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radius x^2+2x+y^2-2y=-1

radius

x^{2} + 2 x + y^{2} - 2 y = - 1

r = 1

Solution steps

x^{2} + 2 x + y^{2} - 2 y = - 1

Rewrite

x^{2} + 2 x + y^{2} - 2 y = - 1

in the form of the standard circle equation

(x - (- 1))^{2} + (y - 1)^{2} = 1^{2}

Therefore the circle properties are:

(a, b) = (- 1, 1), r = 1

And the radius is:

r = 1

(x - 9)^{2} + (y - 4)^{2} = 25

x^{2} + y^{2} - 2 x + 2 y - 7 = 0

x^{2} + y^{2} - 10 x + 7 y - 29 = 0

9 x^{2} + 54 x + 9 y^{2} - 6 y + 28 = 0

x^{2} + y^{2} + 6 x + 5 y = - \frac{45}{4}