What is the radius x^2+y^2+10x-16y=-80 ?

The radius x^2+y^2+10x-16y=-80 is r=3

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radius x^2+y^2+10x-16y=-80

radius

x^{2} + y^{2} + 10 x - 16 y = - 80

r = 3

Solution steps

x^{2} + y^{2} + 10 x - 16 y = - 80

Rewrite

x^{2} + y^{2} + 10 x - 16 y = - 80

in the form of the standard circle equation

(x - (- 5))^{2} + (y - 8)^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (- 5, 8), r = 3

And the radius is:

r = 3

(x + 2)^{2} + (y - 1)^{2} = 16

(x - 3)^{2} + (y - 1)^{2} = 4

(x + 0)^{2} + (y - 0)^{2} = 22

(x - 3)^{2} + (y - 1)^{2} = 9

(x - 4)^{2} + (y + 1)^{2} = 9