What is ((x-4)^2}{36}-\frac{(y-2)^2)/9 =1 ?

The solution to ((x-4)^2}{36}-\frac{(y-2)^2)/9 =1 is Hyperbola with (h,k)=(4,2),a=6,b=3

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((x-4)^2}{36}-\frac{(y-2)^2)/9 =1

\frac{( x - 4 ) ^{2}}{36} - \frac{( y - 2 ) ^{2}}{9} = 1

(h, k) = (4, 2), a = 6, b = 3

Solution steps

\frac{( x - 4 ) ^{2}}{36} - \frac{( y - 2 ) ^{2}}{9} = 1

Rewrite

\frac{( x - 4 ) ^{2}}{36} - \frac{( y - 2 ) ^{2}}{9} = 1

in the form of a standard hyperbola equation

\frac{( x - 4 ) ^{2}}{6 ^{2}} - \frac{( y - 2 ) ^{2}}{3 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (4, 2), a = 6, b = 3

f (x) = x^{2} + 4

\frac{y ^{2}}{25} - \frac{x ^{2}}{16} = 1

\frac{x ^{2}}{169} + \frac{y ^{2}}{25} = 1

2 x - y^{2} = 4

f (x) = x^{2} - 24 x - 12

What is ((x-4)^2}{36}-\frac{(y-2)^2)/9 =1 ?
The solution to ((x-4)^2}{36}-\frac{(y-2)^2)/9 =1 is Hyperbola with (h,k)=(4,2),a=6,b=3