What is the radius 4x^2+4y^2=128 ?

The radius 4x^2+4y^2=128 is r=4sqrt(2)

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radius 4x^2+4y^2=128

radius

4 x^{2} + 4 y^{2} = 128

r = 42

Solution steps

4 x^{2} + 4 y^{2} = 128

Rewrite

4 x^{2} + 4 y^{2} = 128

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = (42)^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 42

And the radius is:

r = 42

(x - 2)^{2} + (y - 1)^{2} = 49

2 (x + 1)^{2} + 2 (y - 3)^{2} = 5

x^{2} - 3 x + y^{2} + 3 y - 5 = 0

x^{2} + y^{2} - 14 x + 2 y + 14 = 0

x^{2} + y^{2} + 8 x - 2 y + 15 = 0