What is the radius (x+5)^2+y^2=4 ?

The radius (x+5)^2+y^2=4 is r=2

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radius (x+5)^2+y^2=4

radius

(x + 5)^{2} + y^{2} = 4

r = 2

Solution steps

(x + 5)^{2} + y^{2} = 4

Rewrite

(x + 5)^{2} + y^{2} = 4

in the form of the standard circle equation

(x - (- 5))^{2} + (y - 0)^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (- 5, 0), r = 2

And the radius is:

r = 2

x^{2} + 2 x + y^{2} - 6 y = 0

x^{2} + y^{2} - 6 x + 6 y + 2 = 0

x^{2} + y^{2} - 4 x + 8 y + 19 = 0

x^{2} + y^{2} = 125

x^{2} + y^{2} - 4 x + 8 y + 11 = 0