What is the radius x^2+y^2+2y-15=0 ?

The radius x^2+y^2+2y-15=0 is r=4

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radius x^2+y^2+2y-15=0

radius

x^{2} + y^{2} + 2 y - 15 = 0

r = 4

Solution steps

x^{2} + y^{2} + 2 y - 15 = 0

Rewrite

x^{2} + y^{2} + 2 y - 15 = 0

in the form of the standard circle equation

(x - 0)^{2} + (y - (- 1))^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (0, - 1), r = 4

And the radius is:

r = 4

x^{2} + y^{2} = 144

(x - \frac{6}{5})^{2} + (y + \frac{1}{3})^{2} = \frac{49}{9}

x^{2} + y^{2} = 4

x^{2} + y^{2} + 8 x - 6 y + 24 = 0

2 x^{2} + 2 y^{2} + 16 x - 6 y - 18 = 0