What is the radius (x-(-5))^2+(y-7)^2=3^2 ?

The radius (x-(-5))^2+(y-7)^2=3^2 is r=3

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radius (x-(-5))^2+(y-7)^2=3^2

radius

(x - (- 5))^{2} + (y - 7)^{2} = 3^{2}

r = 3

Solution steps

(x - (- 5))^{2} + (y - 7)^{2} = 3^{2}

Rewrite

(x - (- 5))^{2} + (y - 7)^{2} = 3^{2}

in the form of the standard circle equation

(x - (- 5))^{2} + (y - 7)^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (- 5, 7), r = 3

And the radius is:

r = 3

(x + 6)^{2} + (y - 1)^{2} = 16

x^{2} + y^{2} - 7 x = 15 - 2 y

(x - 3)^{2} + (y + 5)^{2} = 25

x^{2} + (y + 4)^{2} = 121

(x + 2)^{2} + (y + 4)^{2} = 4

What is the radius (x-(-5))^2+(y-7)^2=3^2 ?
The radius (x-(-5))^2+(y-7)^2=3^2 is r=3