What is the radius x^2+(y+2)^2=(sqrt(20)^2) ?

The radius x^2+(y+2)^2=(sqrt(20)^2) is r=sqrt((\sqrt{20))^2}

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radius x^2+(y+2)^2=(sqrt(20)^2)

radius

x^{2} + (y + 2)^{2} = (20^{2})

r = (20)^{2}

Solution steps

x^{2} + (y + 2)^{2} = (20)^{2}

Rewrite

x^{2} + (y + 2)^{2} = 20^{2}

in the form of the standard circle equation

(x - 0)^{2} + (y - (- 2))^{2} = ((20)^{2})^{2}

Therefore the circle properties are:

(a, b) = (0, - 2), r = (20)^{2}

And the radius is:

r = (20)^{2}

x^{2} + y^{2} - 10 x - 8 y + 32 = 0

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x^{2} + 4 x + y^{2} - 6 y + 9 = 0

x^{2} + y^{2} - 8 x - 8 y + 28 = 0

4 x^{2} + 4 y^{2} + 40 x - 32 y = 0

What is the radius x^2+(y+2)^2=(sqrt(20)^2) ?
The radius x^2+(y+2)^2=(sqrt(20)^2) is r=sqrt((\sqrt{20))^2}