What is the radius x^2+8x+y^2-2y=9 ?

The radius x^2+8x+y^2-2y=9 is r=sqrt(26)

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radius x^2+8x+y^2-2y=9

radius

x^{2} + 8 x + y^{2} - 2 y = 9

r = 26

Solution steps

x^{2} + 8 x + y^{2} - 2 y = 9

Rewrite

x^{2} + 8 x + y^{2} - 2 y = 9

in the form of the standard circle equation

(x - (- 4))^{2} + (y - 1)^{2} = (26)^{2}

Therefore the circle properties are:

(a, b) = (- 4, 1), r = 26

And the radius is:

r = 26

x^{2} + y^{2} + 12 y - 108 = 0

x^{2} + 6 x + y^{2} - 2 y - 15 = 0

x^{2} + y^{2} - 8 x + 10 y - 8 = 0

X^{2} + Y^{2} = 49

x^{2} + (y - 2)^{2} = 36