What is the radius 6(x-3)^2+6(y+7)^2=216 ?

The radius 6(x-3)^2+6(y+7)^2=216 is r=6

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radius 6(x-3)^2+6(y+7)^2=216

radius

6 (x - 3)^{2} + 6 (y + 7)^{2} = 216

r = 6

Solution steps

6 (x - 3)^{2} + 6 (y + 7)^{2} = 216

Rewrite

6 (x - 3)^{2} + 6 (y + 7)^{2} = 216

in the form of the standard circle equation

(x - 3)^{2} + (y - (- 7))^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (3, - 7), r = 6

And the radius is:

r = 6

x^{2} + y^{2} - 4 x + 9 x = 16

(x + 2)^{2} + (y - 3)^{2} = (- 6)^{2}

x^{2} + y^{2} - 10 x + 4 y + 25 = 0

(x + 1)^{2} + (y + 3)^{2} = 4

x^{2} + y^{2} - 64 = 0

What is the radius 6(x-3)^2+6(y+7)^2=216 ?
The radius 6(x-3)^2+6(y+7)^2=216 is r=6