What is the radius x^2+y^2+9x-9y-17=0 ?

The radius x^2+y^2+9x-9y-17=0 is r=sqrt(115/2)

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radius x^2+y^2+9x-9y-17=0

radius

x^{2} + y^{2} + 9 x - 9 y - 17 = 0

r = \frac{115}{2}

Solution steps

x^{2} + y^{2} + 9 x - 9 y - 17 = 0

Rewrite

x^{2} + y^{2} + 9 x - 9 y - 17 = 0

in the form of the standard circle equation

(x - (- \frac{9}{2}))^{2} + (y - \frac{9}{2})^{2} = (\frac{115}{2})^{2}

Therefore the circle properties are:

(a, b) = (- \frac{9}{2}, \frac{9}{2}), r = \frac{115}{2}

And the radius is:

r = \frac{115}{2}

x^{2} + y^{2} + 6 x + 8 y + 24 = 0

x^{2} + y^{2} + 8 x - 6 y = 6

x^{2} + y^{2} - 8 x + 8 = 0

(x + 2)^{2} + (y - 4)^{2} = 25

x^{2} + 2 x + y^{2} = 0

What is the radius x^2+y^2+9x-9y-17=0 ?
The radius x^2+y^2+9x-9y-17=0 is r=sqrt(115/2)