What is the radius x^2+16x+y^2-12y=0 ?

The radius x^2+16x+y^2-12y=0 is r=10

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radius x^2+16x+y^2-12y=0

radius

x^{2} + 16 x + y^{2} - 12 y = 0

r = 10

Solution steps

x^{2} + 16 x + y^{2} - 12 y = 0

Rewrite

x^{2} + 16 x + y^{2} - 12 y = 0

in the form of the standard circle equation

(x - (- 8))^{2} + (y - 6)^{2} = 1 0^{2}

Therefore the circle properties are:

(a, b) = (- 8, 6), r = 10

And the radius is:

r = 10

(x - 2.5)^{2} + (y - 0.5)^{2} = 14.5

(x - 5)^{2} + (y - 12)^{2} = 9

4 x^{2} + 4 y^{2} - 16 = 0

3 (x - 5)^{2} + 3 y^{2} = 27

x^{2} + y^{2} + 12 y = - 32