What is the radius x^2+y^2-2y-15=0 ?

The radius x^2+y^2-2y-15=0 is r=4

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radius x^2+y^2-2y-15=0

radius

x^{2} + y^{2} - 2 y - 15 = 0

r = 4

Solution steps

x^{2} + y^{2} - 2 y - 15 = 0

Rewrite

x^{2} + y^{2} - 2 y - 15 = 0

in the form of the standard circle equation

(x - 0)^{2} + (y - 1)^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (0, 1), r = 4

And the radius is:

r = 4

x^{2} + y^{2} + 2 x = 3 y

x^{2} + 2 x + y^{2} + 4 y - 6 = 0

x^{2} + y^{2} - 10 x - 10 y = - 1

x^{2} + y^{2} - 4 x + 2 y + 4 = 0

x^{2} + y^{2} - 4 x + 16 y + 4 = 0