What is the radius (x-2)^2+(y-5)^2=9 ?

The radius (x-2)^2+(y-5)^2=9 is r=3

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radius (x-2)^2+(y-5)^2=9

radius

(x - 2)^{2} + (y - 5)^{2} = 9

r = 3

Solution steps

(x - 2)^{2} + (y - 5)^{2} = 9

Rewrite

(x - 2)^{2} + (y - 5)^{2} = 9

in the form of the standard circle equation

(x - 2)^{2} + (y - 5)^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (2, 5), r = 3

And the radius is:

r = 3

x^{2} + y^{2} - 8 = 0

(x - 2)^{2} + (y + 3)^{2} = 9

3 y^{2} + 3 x^{2} + 24 x + 32 = 0

(x + 4)^{2} + (y - 3)^{2} = 25

(x - 1)^{2} + (y - 4)^{2} = 25