What is the radius x^2+y^2+6x+2y-54=0 ?

The radius x^2+y^2+6x+2y-54=0 is r=8

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radius x^2+y^2+6x+2y-54=0

radius

x^{2} + y^{2} + 6 x + 2 y - 54 = 0

r = 8

Solution steps

x^{2} + y^{2} + 6 x + 2 y - 54 = 0

Rewrite

x^{2} + y^{2} + 6 x + 2 y - 54 = 0

in the form of the standard circle equation

(x - (- 3))^{2} + (y - (- 1))^{2} = 8^{2}

Therefore the circle properties are:

(a, b) = (- 3, - 1), r = 8

And the radius is:

r = 8

2 x^{2} + 2 y^{2} = 8

x^{2} + y^{2} - 10 x + 2 y + 17 = 0

(x - 1)^{2} + (y + 2)^{2} = 16

x^{2} + y^{2} + 6 x - 4 y + 12 = 0

(x - 2)^{2} + (y - (- 5))^{2} = 97