What is the circumference x^2+y^2-18x-14y+124=0 ?

The circumference x^2+y^2-18x-14y+124=0 is C=2sqrt(6)pi

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circumference x^2+y^2-18x-14y+124=0

circumference

x^{2} + y^{2} - 18 x - 14 y + 124 = 0

C = 26 π

Solution steps

C = 2 π r

Find the radius

Radius given

x^{2} + y^{2} - 18 x - 14 y + 124 = 0 : r = 6

C = 26 π

x^{2} + y^{2} = 7

x^{2} + y^{2} - 6 x + 8 y = 144

x^{2} + y^{2} = 4

(x - 2)^{2} + y^{2} = 16

x^{2} + y^{2} = 49

What is the circumference x^2+y^2-18x-14y+124=0 ?
The circumference x^2+y^2-18x-14y+124=0 is C=2sqrt(6)pi