What is the circumference (x-5)^2+(y+2)^2=16 ?

The circumference (x-5)^2+(y+2)^2=16 is C=8pi

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circumference (x-5)^2+(y+2)^2=16

circumference

(x - 5)^{2} + (y + 2)^{2} = 16

C = 8 π

Solution steps

C = 2 π r

Find the radius

Radius given

(x - 5)^{2} + (y + 2)^{2} = 16 : r = 4

C = 2 π 4

Refine

C = 8 π

x^{2} + y^{2} - 25 = 0

x^{2} + y^{2} = 12

x^{2} + y^{2} - 2 x - 6 y - 6 = 0

(x + 2)^{2} + (y - 1)^{2} = 4

x^{2} - 2 x + y^{2} + 4 y = 4

What is the circumference (x-5)^2+(y+2)^2=16 ?
The circumference (x-5)^2+(y+2)^2=16 is C=8pi