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Popular >

circumference x^2+y^2<=+16

Solution

circumference

x^{2} + y^{2} \leq + 16

Solution

C = 8 π

Solution steps

C = 2 π r

Find the radius

Radius given

x^{2} + y^{2} \leq + 16 : r = 4

C = 2 π 4

Refine

C = 8 π

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Frequently Asked Questions (FAQ)

What is the circumference x^2+y^2<=+16 ?
The circumference x^2+y^2<=+16 is C=8pi