What is the circumference x^2+y^2-6x+4y+8=0 ?

The circumference x^2+y^2-6x+4y+8=0 is C=2sqrt(5)pi

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circumference x^2+y^2-6x+4y+8=0

circumference

x^{2} + y^{2} - 6 x + 4 y + 8 = 0

C = 25 π

Solution steps

C = 2 π r

Find the radius

Radius given

x^{2} + y^{2} - 6 x + 4 y + 8 = 0 : r = 5

C = 25 π

x^{2} + (y - 7)^{2} = 36

(x - 5)^{2} + (y - 2)^{2} = 25

x^{2} + (y - 1)^{2} = 4

x^{2} + y^{2} - 8 x - 10 y + 40 = 0

x^{2} + 6 x + y^{2} - 8 y = 0

What is the circumference x^2+y^2-6x+4y+8=0 ?
The circumference x^2+y^2-6x+4y+8=0 is C=2sqrt(5)pi