What is the circumference 1/2 x^2+1/2 y^2=16 ?

The circumference 1/2 x^2+1/2 y^2=16 is C=8sqrt(2)pi

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circumference 1/2 x^2+1/2 y^2=16

circumference

\frac{1}{2} x^{2} + \frac{1}{2} y^{2} = 16

C = 82 π

Solution steps

C = 2 π r

Find the radius

Radius given

\frac{1}{2} x^{2} + \frac{1}{2} y^{2} = 16 : r = 42

C = 2 π 42

Refine

C = 82 π

x^{2} + y^{2} - 12 x + 20 y + 72 = 0

x^{2} + y^{2} + 4 x + 12 y - 104 = 0

c i rc l e, f in d C i rc u m f ere n ce, g i v e n r = 3

(x - 5)^{2} + (y - 1)^{2} = 4

x^{2} + y^{2} \leq 1

What is the circumference 1/2 x^2+1/2 y^2=16 ?
The circumference 1/2 x^2+1/2 y^2=16 is C=8sqrt(2)pi