What is the circumference (x-4)^2+(y-(-4))^2=16 ?

The circumference (x-4)^2+(y-(-4))^2=16 is C=8pi

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circumference (x-4)^2+(y-(-4))^2=16

circumference

(x - 4)^{2} + (y - (- 4))^{2} = 16

C = 8 π

Solution steps

C = 2 π r

Find the radius

Radius given

(x - 4)^{2} + (y - (- 4))^{2} = 16 : r = 4

C = 2 π 4

Refine

C = 8 π

x^{2} + y^{2} - 4 = 0

x^{2} + y^{2} + 8 x - 2 y + 15 = 0

3 x^{2} + 3 y^{2} - 12 x + 6 y - 12 = 0

x^{2} - 4 x + y^{2} + 8 y - 5 = 0

3 x^{2} + 3 y^{2} = 75

What is the circumference (x-4)^2+(y-(-4))^2=16 ?
The circumference (x-4)^2+(y-(-4))^2=16 is C=8pi