What is the circumference 4x^2+4y^2+28x-28y-24=0 ?

The circumference 4x^2+4y^2+28x-28y-24=0 is C=2pisqrt(61/2)

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circumference 4x^2+4y^2+28x-28y-24=0

circumference

4 x^{2} + 4 y^{2} + 28 x - 28 y - 24 = 0

C = 2 π \frac{61}{2}

Solution steps

C = 2 π r

Find the radius

Radius given

4 x^{2} + 4 y^{2} + 28 x - 28 y - 24 = 0 : r = \frac{61}{2}

C = 2 π \frac{61}{2}

x^{2} + 14 x + y^{2} - 6 y - 23 = 0

x^{2} + y^{2} = 8

9 x^{2} + 9 y^{2} + 18 x - 18 y + 14 = 0

(x - 3)^{2} + (y - 2)^{2} = 9

(x - 3)^{2} + (y - 2)^{2} = 4

What is the circumference 4x^2+4y^2+28x-28y-24=0 ?
The circumference 4x^2+4y^2+28x-28y-24=0 is C=2pisqrt(61/2)