What is the circumference (x-(-1))^2+(y-2)^2=6^2 ?

The circumference (x-(-1))^2+(y-2)^2=6^2 is C=12pi

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circumference (x-(-1))^2+(y-2)^2=6^2

circumference

(x - (- 1))^{2} + (y - 2)^{2} = 6^{2}

C = 12 π

Solution steps

C = 2 π r

Find the radius

Radius given

(x - (- 1))^{2} + (y - 2)^{2} = 6^{2} : r = 6

C = 2 π 6

Refine

C = 12 π

(x - 1)^{2} + (y - 6)^{2} = 25

x^{2} + y^{2} + 8 x - 2 y - 19 = 0

(x - 2)^{2} + (y - 5)^{2} = 16

x^{2} + y^{2} - 18 x - 6 y - 10 = 0

x^{2} + y^{2} = 2.5

What is the circumference (x-(-1))^2+(y-2)^2=6^2 ?
The circumference (x-(-1))^2+(y-2)^2=6^2 is C=12pi