What is the circumference (x+1)^2+(y+8)^2=14 ?

The circumference (x+1)^2+(y+8)^2=14 is C=2sqrt(14)pi

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circumference (x+1)^2+(y+8)^2=14

circumference

(x + 1)^{2} + (y + 8)^{2} = 14

C = 214 π

Solution steps

C = 2 π r

Find the radius

Radius given

(x + 1)^{2} + (y + 8)^{2} = 14 : r = 14

C = 214 π

c i rc l e, f in d C i rc u m f ere n ce, g i v e n r = 10

x^{2} + y^{2} + x + 3 y - 104 = 0

6 x^{2} + 6 y^{2} = 12 x + 12 y + 6

x^{2} + y^{2} + 8 x + 4 y + 2 = 0

x^{2} + y^{2} + 6 x - 4 y - 12 = 0

What is the circumference (x+1)^2+(y+8)^2=14 ?
The circumference (x+1)^2+(y+8)^2=14 is C=2sqrt(14)pi