What is the circumference x^2+y^2+18x-24y-69=0 ?

The circumference x^2+y^2+18x-24y-69=0 is C=14sqrt(6)pi

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

circumference x^2+y^2+18x-24y-69=0

circumference

x^{2} + y^{2} + 18 x - 24 y - 69 = 0

C = 146 π

Solution steps

C = 2 π r

Find the radius

Radius given

x^{2} + y^{2} + 18 x - 24 y - 69 = 0 : r = 76

C = 2 π 76

Refine

C = 146 π

x^{2} - 10 x + y^{2} + 6 y - 1 = 0

(x - 0)^{2} + (y + 0)^{2} = 7^{2}

(x + 7)^{2} + (y - 3)^{2} = 9

x^{2} + y^{2} = 800

(x - 3)^{2} + (y - 5)^{2} = 1

What is the circumference x^2+y^2+18x-24y-69=0 ?
The circumference x^2+y^2+18x-24y-69=0 is C=14sqrt(6)pi