What is the circumference 2x^2+2y^2-8x-12y+8=0 ?

The circumference 2x^2+2y^2-8x-12y+8=0 is C=6pi

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circumference 2x^2+2y^2-8x-12y+8=0

circumference

2 x^{2} + 2 y^{2} - 8 x - 12 y + 8 = 0

C = 6 π

Solution steps

C = 2 π r

Find the radius

Radius given

2 x^{2} + 2 y^{2} - 8 x - 12 y + 8 = 0 : r = 3

C = 2 π 3

Refine

C = 6 π

(x - 3)^{2} + (y + 4)^{2} = 8

x^{2} + y^{2} - 6 y = 16

2 x^{2} + 2 y^{2} + 10 x - 6 y + 3 = 0

4 x^{2} + 4 y^{2} + 12 x - 4 y - 88 = 0

x^{2} - 4 x + y^{2} + 2 y + 1 = 0

What is the circumference 2x^2+2y^2-8x-12y+8=0 ?
The circumference 2x^2+2y^2-8x-12y+8=0 is C=6pi